- ￥5000
- GeneTex
- 美国
- GTX80656
- 2025年07月12日
- WB, ICC/IF, IP
- Mouse
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- 详细信息
- 文献和实验
- 技术资料
- 免疫原：
A synthetic peptide (DYKDDDDK) coupled to KLH.
- 亚型：
IgG2b
- 形态：
Liquid
- 保存条件：
Store as concentrated solution. Centrifuge briefly prior to opening vial. For short-term storage (1-2 weeks), store at 4ºC. For long-term storage, aliquot and store at -20ºC or below. Avoid multiple freeze-thaw cycles.
- 克隆性：
Monoclonal
- 标记物：
Unconjugated
- 保质期：
12 months from the shipping date of the product.
- 目录编号：
GTX80656
- 级别：
Primary Antibodies
- 库存：
Available
- 供应商：
GeneTex
- 宿主：
Mouse
- 应用范围：
WB, ICC/IF, IP
- 浓度：
1 mg/ml (Please refer to the vial label for the specific concentration.)
- 靶点：
Recognizes over-expressed proteins containing DYKDDDDK epitope tag fused to either amino- or carboxy-termini of targeted proteins in transfected mammalian cells.
- 抗体英文名：
DDDDK tag antibody [F.G2]
- 抗体名：
DDDDK tag 抗体 [F.G2]
- 规格：
100 μg
Western Blot analysis of 293 cells transfected with DYKDDDK-tagged vectors at different concentration(0.5mg/ml),
Lane 4:lowest concentration(0.1ug/ml)
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文献和实验Li Z et al., Sci Rep 2018 (PMID:30038404)
Sud N et al., Am J Physiol Lung Cell Mol Physiol 2008 (PMID:18192589)
Chen Z et al., Nucleic Acids Res 2013 (PMID:23956220)
Production of Bispecif ic and Trispecific F(ab)2 and F(ab)3 Antibody Derivatives
Bispecific antibodies (BsAbs) are hybrid molecules designed to combine two antibodies with different specificities. This dual specificity has led to their application in a variety of diagnostic situations that require the crosslinking
干货 | CUT and Tag 核心酶 Hyperactive PA/PG-Tn5 Transposase 大解密
CUT&Tag（Cleavage Under Targets and Tagmentation）是蛋白-DNA 互作的一大革新技术，它不需要使用甲醛交联以及免疫共沉淀，而是通过针对靶蛋白（如转录因子、染色质重塑蛋白）的抗体和 Protein A/G 的介导，使得与 Protein A/G 融合的 Tn5 酶(Tagmentase)在切割 DNA 片段的同时在序列两端加上测序接头，经 PCR 扩增后即可形成用于高通量测序的文库（见图 1 ）。CUT &Tag 技术具有细胞投入量低、信噪
. When Biotinylating an antibody, you can test the antibody by Flow Cytometry. 6. F/P Ratio: a) Dilute an aliquot of FITC-Ig complex with buffer so that the Absorbance at 280nm (A280) is less than 2.0 b) Determine and record A280 and A492. c) Calculate
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