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- 文献和实验
- 技术资料
- 保存条件:
Powder: -20°C, 3 years; 4°C, 2 years.In solvent: -80°C, 6 months; -20°C, 1 month.
- 库存:
货期:1-2天
- 供应商:
MedChemExpress LLC
- CAS号:
1435265-06-7
- 规格:
10 mM * 1 mL/1 mg/5 mg/10 mg/25 mg/50 mg
| 规格: | 10 mM * 1 mL | 产品价格: | ¥1446.0 |
|---|---|---|---|
| 规格: | 1 mg | 产品价格: | ¥636.0 |
| 规格: | 5 mg | 产品价格: | ¥1400.0 |
| 规格: | 10 mg | 产品价格: | ¥2100.0 |
| 规格: | 25 mg | 产品价格: | ¥3600.0 |
| 规格: | 50 mg | 产品价格: | ¥5200.0 |
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HCH6-1
CAS No. : 1435265-06-7
MCE 国际站:HCH6-1
产品活性:HCH6-1 是一种有效的甲酰肽受体 1 (FPR1) 的竞争性二肽拮抗剂。HCH6-1 抑制 fMLF (FPR1激动剂) 特异性激活的人中性粒细胞的趋化性、超氧阴离子生成和弹性酶释放。动物实验中,HCH6-1 对急性肺损伤 (ALI) 具有保护作用,可用于 FPR1 参与的炎症性肺部疾病的研究。
研究领域:GPCR/G Protein
作用靶点:Formyl Peptide Receptor (FPR)
In Vitro: In a cell-impermeable cytochrome c reduction assay, HCH6-1 significantly inhibits superoxide anion generation in fMLF (FPR1 agonist)-activated neutrophils with an IC50 of 0.32 μM. HCH6-1 has fewer inhibitory effects in WKYMVm (dual FPR1/FPR2 agonist)- and MMK1 (FPR2 agonist)-activated neutrophils, with IC50s of 4.98±0.27 μM and 17.68±2.77 μM, respectively.
HCH6-1 does not induce LDH release even at 30 μM, so it does not have cytotoxic effects in human neutrophils. HCH6-1 does not alter the level of xanthine/xanthine oxidase superoxide anion and DPPH radical in cell-free systems.
HCH6-1 significantly inhibits elastase release in fMLF-activated neutrophils, with an IC50 of 0.57 μM. However, in neutrophils triggered by WKYMVm or MMK1, HCH6-1 inhibits elastase release at higher concentrations, with IC50s of 5.22±0.69 μM and 10.00±0.65 μM, respectively.
In Vivo: HCH6-1 (intraperitoneal injection; 50 mg/kg; 1 h before LPS spray or 30 min after LPS spray) alone does not induce airspace inflammation. HCH6-1 pretreatment reduces inflammatory cell infiltration and distortion of pulmonary architecture in the presence of LPS. HCH6-1 posttreatment shows inhibitory effects on neutrophil accumulation and lung damage in LPS-induced ALI mice.
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佚名 方差齐性检验的方法是以两方差中较大的方差为分子,较小的方差为分母求一比值(称为F值),然后将求得的F值与临界值比较,看相差是否显著,现举一例说明。 例7.10 某单位测定了蓄电池厂工人32号,得尿氨基乙酰丙酸(mg/l)的平均含量为7.06,方差为42.3072,又测定了化工厂工人6名,得平均含量为3.48,方差为0.9047,试比较两方差的相差
佚名 方差齐性检验的方法是以两方差中较大的方差为分子,较小的方差为分母求一比值(称为F值),然后将求得的F值与临界值比较,看相差是否显著,现举一例说明。 例7.10 某单位测定了蓄电池厂工人32号,得尿氨基乙酰丙酸(mg/l)的平均含量为7.06,方差为42.3072,又测定了化工厂工人6名,得平均含量为3.48,方差为0.9047,试比较两方差的相差
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