![VAMP5 antibody [3E5]产品图](https://img1.dxycdn.com/2022/0329/352/4189288317216020453-14.jpg)
- ￥1700 - 4000
- GeneTex
- 美国
- GTX632270
- 2026年05月27日
- WB, ICC/IF
- Mouse
- Human
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- 文献和实验
- 技术资料
- 免疫原：
The immunogen used to generate this antibody corresponds to human VAMP5.
- 亚型：
IgG2a
- 形态：
Liquid
- 保存条件：
Store as concentrated solution. Centrifuge briefly prior to opening vial. For short-term storage (1-2 weeks), store at 4ºC. For long-term storage, aliquot and store at -20ºC or below. Avoid multiple freeze-thaw cycles.
- 克隆性：
Monoclonal
- 标记物：
Unconjugated
- 适应物种：
Human
- 保质期：
12 months from the shipping date of the product.
- 抗原来源：
Human
- 目录编号：
GTX632270
- 级别：
Primary Antibodies
- 库存：
Available
- 供应商：
GeneTex
- 宿主：
Mouse
- 应用范围：
WB, ICC/IF
- 浓度：
1 mg/ml (Please refer to the vial label for the specific concentration.)
- 靶点：
VAMP5
- 抗体英文名：
VAMP5 antibody [3E5]
- 抗体名：
VAMP5 抗体 [3E5]
- 规格：
100 μl/25 μl
| 规格： | 100 μl | 产品价格： | ￥4000.0 |
|---|---|---|---|
| 规格： | 25 μl | 产品价格： | ￥1700.0 |
Non-transfected (–) and transfected (+) 293T whole cell extracts (30 μg) were separated by 15% SDS-PAGE, and the membrane was blotted with VAMP5 antibody [3E5] (GTX632270) diluted at 1:5000. The HRP-conjugated anti-mouse IgG antibody (GTX213111-01) was used to detect the primary antibody.
ICC/IF analysis of transfected NRK cells (V5V4-GFP) using GTX632270 VAMP5 antibody [3E5].
Red : Primary antibody
ICC/IF analysis of pLEGFP-C1-hV5p transfected HeLa cells using GTX632270 VAMP5 antibody [3E5].
Red : Primary antibody
WB analysis of Vamp5-GST protein using GTX632270 VAMP5 antibody [3E5].
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文献和实验Polyclonal and Monoclonal Antibodies
Polyclonal Antibody Immunization of Mice: Injections should be made at intervals of at least two weeks.. We have been using either of the two following adjuvants with success: Freund adjuvant and MPL+TDM adjuvant ( RIBI ImmunoChem
【求助】什么是micro-array analysis，怎么翻译？
zifanqie_00 什么是micro-array analysis，怎么翻译？ shusheng2006 微矩阵分析，应该就是基因芯片吧 eulota 基因芯片中的微阵列分析 翻译参考 cnki翻译助手 链接为 http://dict.cnki.net/dict_result.aspx?searchword=micro-array&tjType=sentence&t=%e5
in log phase (3 E5 - 1E6 cells / ml). Determine the volume needed which will give you 100 cells. Add the 100 cells to 25 ml of IMDM-m and plate 250 ml of the suspension in each well. Therefore, each well should get 1 cell delivered
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